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![In a common emitter transistor circuit the base current is \\[40\\mu {\\text{A}}\\], then \\[{V_{BE}}\\] is: \n \n \n \n \n A) $2V$B) $0.2V$C) $0.8V$D) $Zero$ \t](https://www.vedantu.com/question-sets/e48fccc2-f921-4cff-b6ca-b66762aa3b5c4453938871296625310.png "In a common emitter transistor circuit the base current is \\[40\\mu {\\text{A}}\\], then \\[{V_{BE}}\\] is: \n \n \n \n \n A) $2V$B) $0.2V$C) $0.8V$D) $Zero$ \t")
In a common emitter transistor circuit the base current is \\[40\\mu {\\text{A}}\\], then \\[{V_{BE}}\\] is: \n \n \n \n \n A) $2V$B) $0.2V$C) $0.8V$D) $Zero$ \t
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In the given transistor circuit, the base current is 35 μ A. The value of Rb is
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